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EAD is a triangle and BCDE is a parallelogram, with AB = BE. Given ∠DBC = 39° and ∠BCD = 73°, find ∠EAB.
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One angle gives you the next, until you reach the angle asked for.
In this one. B sits on the straight line AD, so the parallelogram angle left over at B (∠EBD = 68°) is the exterior angle of the isosceles triangle ABE — it equals the two equal base angles added together, so ∠EAB is just half of it.
A figure has several angles marked with only one or two values given, and words like 'isosceles', 'parallel', or 'straight line' point to which rule to use first.
Children apply an angle rule to the wrong triangle or the wrong straight line in a crowded figure, or stop one step before the angle actually asked for.
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