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Question P6 Overlap and cancel

Rectangle ACEG — the shaded triangles

Rectangle ACEG is split by BF into rectangles ABFG and BCEF. H is on AG, D is on CE, X is the midpoint of BF. Perimeter of ACEG = 90 cm and AG : AC = 4 : 5. Find (a) AG, and (b) the area shaded — triangles HXF and BXD.

Rectangle ACEG, perimeter 90 cm and AG : AC = 4 : 5, cut into two rectangles by BF, with X the midpoint of BF. The two shaded triangles are HXF and BXD. Drawn to scale; the partition is not down the middle.ACEGBFXHD

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About this method

Overlap and cancel

Two shapes share a region, and the shared part cancels out.

In this one. Both shaded triangles have their base on the same line BF and X is its midpoint, so the two bases are equal (10 cm each) and the two heights are AB and BC — which add to the whole side AC. Where B sits on AC never matters.

Counted twiceA + Bgroup Athe two in bothgroup Bthe same two againCounted oncetake the shared part offin all5 + 4 − 2 = 7

How to spot it

Shapes are joined, stacked, or have a piece cut off, and the question compares a perimeter or length before and after, rather than asking for an area from scratch.

Common mistake

Children assume perimeter changes the same way area does. Joining shapes or cutting off a corner can leave the perimeter unchanged, or change it by a different amount from the area.

Practise a similar question

Challenging 4 identical semicircles overlap in a row. A, B and C are the 3 identical shaded overlaps. The unshaded area is 2125 cm² more than the shaded area. Take π = 3.14. Find (a) the perimeter of the unshaded part, (b) the total…
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